Math, asked by dasbitu868, 11 months ago

(f) The value of cot 15° is​

Answers

Answered by AshishAman1234
1

Answer:

The value of cot 15° is 2+\sqrt{3}2+

3

.

Step-by-step explanation:

The given expression is

\cot(15^{\circ})cot(15

)

It can be written as

\cot(15^{\circ})=\cot(45^{\circ})-30^{\circ})cot(15

)=cot(45

)−30

)

\cot(15^{\circ})=\frac{\cot(45)\cot (30)+1}{\cot(30)-\cot (45)}cot(15

)=

cot(30)−cot(45)

cot(45)cot(30)+1

\cot(15^{\circ})=\frac{(1)(\sqrt{3})+1}{\sqrt{3}-1}cot(15

)=

3

−1

(1)(

3

)+1

\cot(15^{\circ})=\frac{\sqrt{3}+1}{\sqrt{3}-1}cot(15

)=

3

−1

3

+1

Multiply both numerator and denominator by (\sqrt{3}+1)(

3

+1) .

\cot(15^{\circ})=\frac{\sqrt{3}+1}{\sqrt{3}-1}\times \frac{\sqrt{3}+1}{\sqrt{3}+1}cot(15

)=

3

−1

3

+1

×

3

+1

3

+1

\cot(15^{\circ})=\frac{(\sqrt{3}+1)^2}{(\sqrt{3})^2-1^2}cot(15

)=

(

3

)

2

−1

2

(

3

+1)

2

\cot(15^{\circ})=\frac{(3+1+2\sqrt{3}}{3-1}cot(15

)=

3−1

(3+1+2

3

\cot(15^{\circ})=\frac{(2(2+\sqrt{3})}{2}=2+\sqrt{3}cot(15

)=

2

(2(2+

3

)

=2+

3

Therefore the value of cot 15° is 2+\sqrt{3}2+

3

.

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