Question

f the water falls from a dam into a turbine wheel 20 m below. Then the velocity of water
when it falls on the turbine is:

Answer 1

Answer:

20m/s

Explanation:

V=√2gh

V=√2×10×20

V=√400

V=20m/s

Answer 2

Given:

Water falls from a dam into a turbine wheel 20 m below.

To find:

Velocity of water when it reaches turbine wheel?

Calculation:

• We will assume that the turbine wheel has negligible height and is present on the ground.

Applying EQUATIONS OF KINEMATICS:

$\rm {v}^{2} = {u}^{2} + 2as$

• Here acceleration is equal to g = 9.8 m/s².

$\rm \implies \: {v}^{2} = {u}^{2} + 2gs$

$\rm \implies \: {v}^{2} = {0}^{2} + (2 \times 9.8 \times 20)$

$\rm \implies \: {v}^{2} = 392$

$\rm \implies \: v = \sqrt{392}$

$\rm \implies \: v = 19.79 \: m {s}^{ - 1}$

So, velocity of water near turbine is 19.79 m/s.