Question

f x+1, 3x and 4x+2 are in AP, then the value of x is​

Answer 1

Answer:

ANSWER

Given 

x+1,3x and 4x+2 are in A.P

then 3x−(x+1)=(4x+2)−3x       [Common diff]

⇒2x−1=x+2

⇒x=3