f(x) = 1-cos(4x)/x^2
x not equal to 0, f(0)=8, at x = 0 f is
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Answer:
es, the function will be continuous.
Step-by-step explanation:
In the function,
We have been provided that,
where, x is not equal to 0.
Now,
For solving the given function we have to solve this using the trigonometric identity,
cos4x = cos²2x - sin²2x
also,
sin²2x + cos²2x = 1
So,
On putting these values in the function we get,
Now, as the conditions are given for the limit on the function, we can say that,
That's why the value of the function is a constant.
f(x) = 1 = constant
Therefore, the function will be continuous at, x = 0 as well.
Step-by-step explanation:
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