Question

f(x)=(1-e^(-x))÷(1+e^(-x)) find f'(x)

Answer 1

$f(x) = \frac{1 - {e}^{ - x} }{1 + {e}^{ - x} } \\ f'(x) = \frac{ {e}^{ - x} (1 + {e}^{ - x}) - (1 - {e}^{ - x} )( - {e}^{ - x} }{( {1 + {e}^{ - x} )}^{2} } \\ f'(x) = \frac{2 {e}^{ - x} }{ {(1 + {e}^{ - x} )}^{2} }$
 [TEX]\ boxed{ hope it will help you}[/TEX ]