Question

f(x)= 1/sinxcosx then f'(x)=?​

Answer 1

Answer:

f (×) = 1 /sinxcosx

= cosec x sec x

Step-by-step explanation:

Answer 2

$<marquee>Answer </marquee>$

Let y = f (x) = 1/sinxcosx

y = 1/sinxcosx

On interchanging x 《-》 y,

x = 1/sinycosy

sinycosy = 1/x

y(sincos) = 1/x

y = 1/sinxcosx

.: f'(x) = cosecX secX

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