f(x)=1-x/1+c,x is not equal to zero then f(f(x)+f(f(1/x)).
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Discontinuous at 0
f(x)=e1/x+1e1/x−1f(x)x→0−=limh→0e−1/h+1e−1/h−1f(x)x→0−=limh→0e1/h1+1e1/h1−1=0+10−1=−1f(x)x→0+=limh→0e1/h+1e1/h−1f(x)x→0+=limh→01−
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