Math, asked by avezqureshi14, 1 year ago

f(x)=1/√x^2-1 find domain and range of the following function

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Answered by sprao534

Please see the attachment

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avezqureshi14: Thanks for the answer

sprao534: sorry. the domain is wrong. f(x) is defined if x^2 - 1 is not equal to 0. that is x^2 is not equal to +/-1.so domain is all real numbers except +/-1.

sprao534: range also 1/x^2 - 1=y, 1=x^2 y-y, 1+y/y=x^2. x= root of (1+y/y). y does not lie between - 1and 0.

avezqureshi14: What!

Answered by annebemyself

Please check the attachment.

HOPE IT HELPS :)

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