Question

f(x)=1/x^2/3 is uniformly continuous or not




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Answer 1

Answer:

it is not uniformly continuous , as f(x) is not defined at x=0 ,

at x=0 there is discontinuity

Answer 2

Answer:

Step-by-step explanation:

f(x)=1/x^2/3 has discontinuity at x=0 since f(0) does not exits