f(x)=1/x^2/3 is uniformly continuous or not
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Answer:
it is not uniformly continuous , as f(x) is not defined at x=0 ,
at x=0 there is discontinuity
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Answer:
Step-by-step explanation:
f(x)=1/x^2/3 has discontinuity at x=0 since f(0) does not exits
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