f(x
1
x
2
)=f(x
1
)f(x
2
)∀x
1
,x
2
∈R where \mathrm{y}=\mathrm{f}(\mathrm{x})y=f(x) is a differentiable function, then which of the following must be true?
Answers
Answered by
1
Step-by-step explanation:
f(x)=x
3
+5x+1
f
′
(x)=3x
2
+5>0⇒f is one-one .⋅
Inverse of f is possible in the domain R. So, f is cubic ⇒ f is onto
f is one-one and onto.
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