Math, asked by adabalakasi, 6 months ago

f(x)=1+x+x^2+........ , for |x|<1 then f^-1(2020) is

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Answered by architadedhia

1

Answer:

I didn't understand the question, but who much i have understood i have given answers... I don't know this is right

Step-by-step explanation:

Hope this will help you

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