F x = 2 and y = 3, after subtracting 5x2 – 4y2 + 6y – 3 from 7x2 – 4xy + 8y2 + 5x – 3y, the resulting value of the expression is
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➡HERE IS YOUR ANSWER⬇
Given two terms are :
r = 5x² - 4y² + 6y - 3
and
r' = 7x² - 4xy + 8y² + 5x - 3y
Now,
r' - r
= (7x² - 4xy + 8y² + 5x - 3y) - (5x² - 4y² + 6y - 3)
= 2x² - 4xy + 12y² + 5x - 9y + 3
When, x = 2 and y = 3,
r' - r
= (2×2²) - (4×2×3) + (12×3²) + (5×2) - (9×3) + 3
= 8 - 24 + 108 + 10 - 27 + 3
= 78
⬆HOPE THIS HELPS YOU⬅
Given two terms are :
r = 5x² - 4y² + 6y - 3
and
r' = 7x² - 4xy + 8y² + 5x - 3y
Now,
r' - r
= (7x² - 4xy + 8y² + 5x - 3y) - (5x² - 4y² + 6y - 3)
= 2x² - 4xy + 12y² + 5x - 9y + 3
When, x = 2 and y = 3,
r' - r
= (2×2²) - (4×2×3) + (12×3²) + (5×2) - (9×3) + 3
= 8 - 24 + 108 + 10 - 27 + 3
= 78
⬆HOPE THIS HELPS YOU⬅
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