f ( x ) = 2 x³ +6 x² + 4 x
g ( x ) = x + 3 x + 2
The polynomials f ( x ) and g ( x ) are defined above. Which of the following polynomials is divisible by 2 x + 3 ?
1). h ( x ) = f ( x ) + g ( x )
2). p ( x ) = f ( x ) + 3 g ( x )
3). r ( x ) = 2 f ( x ) + 3 g ( x )
4). s ( x ) = 3 f ( x ) + 2 g ( x )
Answers
now .. applying remainder theorem....
2x+3=0
X==-3/2
now the remainder when f(X) is divided by 2x+3 is
=2(-3/2)³+6(-3/2)²+4(-3/2)
=(-27/4)+54/4-12/4
={-9+54-12}/4
=-15/4≠0
now the remainder when g(X) is divided by 2x+3 is
=(-3/2)²+3(-3/2)+2
=(9/4)-(9/2)+2
=(9-18+4)/4
=-5/4≠0
so both are not the factor of 2x+3
now .....
1). h ( x ) = f ( x ) + g ( x )
=2 x³ +6 x² + 4 x +x ²+ 3 x + 2
=2x³+7x²+7x+2
therefore..
h(-3/2)=2(-3/2)³+7(-3/2)²+7(-3/2)+2
=(-54/4)+(63/4)-(21/2)+2
=[-54+63-42+8]/4≠0
2). p ( x ) = f ( x ) + 3 g ( x )
=2 x³ +6 x² + 4 x +3(x²+ 3 x + 2)
=2x³+9x²+13x+6
therefore
p(-3/2)=2(-3/2)³+9(-3/2)²+13(-3/2)+6=0
p(-3/2)=0
therefore 2x+3 is a factor of P(X)
Answer:=option(2). p ( x ) = f ( x ) + 3 g ( x )
now the remainder when f(X) is divided by 2x+3 is
2(-3/2)³+6(-3/2)²+4(-3/2)
(-27/4)+54/4-12/4
{-9+54-12}/4
-15/4 is not equal to (0)
now the remainder when g(X) is divided by 2x+3 is
(-3/2)²+3(-3/2)+2
(9/4)-(9/2)+2
(9-18+4)/4
-5/4 is not equal to (0)
so both are not the factor of 2x+3
now .
1). h ( x ) = f ( x ) + g ( x )
=2 x³ +6 x² + 4 x +x ²+ 3 x + 2
=2x³+7x²+7x+2
h(-3/2)=2(-3/2)³+7(-3/2)²+7(-3/2)+2
(-54/4)+(63/4)-(21/2)+2
[-54+63-42+8]/4 is not equal to (0)
2) p ( x ) = f ( x ) + 3 g ( x )
2 x³ +6 x² + 4 x +3(x²+ 3 x + 2)
2x³+9x²+13x+6
p×-3/2)=2
(-3/2)³+9(-3/2)²+13(-3/2)+6=0
p×-3/2)=0
therefore 2x+3 is a factor of value P
Answer:=option(2).