Math, asked by adiveppa72, 7 hours ago

f'(x)=(2x+1)^3 find differentiate

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Answered by amendrapdsingh275

0

dydx=6(2x−1)2. Explanation: Let. y=(2x−1)3. dydx=3(2x−1)2(2). dydx=6(2x−1)2.

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