f(x)=2x^2-3x-1, find(x+2)
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If f(x) =2x^2 - 3x - 1
then, f(x + 2) = 2(x+2)^2 - 3(x+2) -1
= 2(x^2 + 4 +4x) - 3x - 6 - 1
= 2x^2 + 8 +8x - 3x -6 - 1
= 2x^2 + 5x +1
So, the value of f(x+2) is 2x^2 +5x +1 . Ans
then, f(x + 2) = 2(x+2)^2 - 3(x+2) -1
= 2(x^2 + 4 +4x) - 3x - 6 - 1
= 2x^2 + 8 +8x - 3x -6 - 1
= 2x^2 + 5x +1
So, the value of f(x+2) is 2x^2 +5x +1 . Ans
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