Math, asked by solocarey11, 11 months ago

f(x)=2x^3+3x^2-11x-6 tjem find the value of f(-1/2)

Answers

Answered by 69420

0

-2(1/2)^3 + 3/4 + 11/2 -6

=0

Answered by venkatavineela3

0

Answer:

Step-by-step explanation:

f(-1/2)=2*(-1/2)^3+3(-1/2)^2-11(-1/2)-6

=-2*1/8+3(1/4)+11/2-6

=1/4+3/4+11/2-6

=1+11/2-6

=-5+11/2

=-10+11/2

=1/2

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