Question

F(x)=2x^4-2x^3-7x^2+3x+6. If it's two zeroes are- root over 3/2 and root over 3/2

Answer 1

Answer:

Step-by-step explanation:

What we have to answer in that question?

Answer 2

F(x) =2x⁴-2x³-7x²+3x+6.

Let x=√3/2

x - √3/2 =0

Similarly

(x-√3/2) (x+√3/2) use identity

x² - 3/2 = 0

2x²-3 = 0

Divide

=2x⁴-2x³-7x²+3x+6 / 2x²-3

= x²-x-2 = 0

x²-2x + x -2 = 0

x ( x - 2) +1 (x-2) =0

(x+1) (x-2)

x= -1 , x = 2