Question

f(x) = 2x-Tan inverse x-log(x+√(1+x²))(x>0) is
increasing in
​

Answer 1

Step-by-step explanation: We have ddxlog(x+1+x2−−−−−√)

=1(x+1+x2−−−−−√)ddx(x+1+x2−−−−−√)

=1(x+1+x2−−−−−√)(1+ddx(1+x2)12)

=1(x+1+x2−−−−−√)(1+12(1+x2)−12ddx(1+x2))

=1(x+1+x2−−−−−√)(1+12(1+x2)−122x)

=1(x+1+x2−−−−−√)(1+x(1+x2)−−−−−−−√)

=1(x+1+x2−−−−−√)(x+1+x2−−−−−√)1+x2−−−−−√

=11+x2−−−−−√

hope you understand it