f(x) = 2x° + x2 – 5x + 2; 2,1,-2
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Answer:
2x2+5x+22x>(x+1)1
⇒2x2+5x+22x−(x+1)1>0
⇒(2x2+5x+2)(x+1)2x(x+1)−2x2−5x−2>0
⇒(2x2+5x+2)(x+1)−3x−2>0
⇒(2x2+4x+x+2)(x+1)−(3x+2)>0
⇒(2x+1)(x+2)(x+1)−(3x+2)>0
⇒x∈(−2,−1)∪(−32,−21)
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