f(x) = 2x² + 5x -9; f(5x - 2)
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The range is y∈(−∞,0)∪(0,+∞)
Explanation:
The function is
f(x)=2x+12x2+5x+2
Factorise the denominator
2x2+5x+2=(x+2)(2x+1)
Therefore,
f(x)=2x+1(x+2)2x+1=1x+2
Let y=1+2⇒ ,y(x+2)=1yx+2y=1yx=1−2yx=-12yy
The denominator must be
≠0y≠0
The range is ly∈(−∞,0)∪(0+∞)graph{(2x+1)/(2x^2+5x+2) [-14.24, 14.24, -7.12, 7.12]}
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