Question

f(x)=2x³-(3x²+17x+12,find 2f(-1)​

Answer 1

given f(X)=2X^3-(3X^2+17X+12)

to find f(-1) we have to substitute-1 in the place of X

f(-1)=2(-1)^3-{3(-1)^2+17(-1)+12}

f(-1)= -2-{3-17+12}

f(-1)= -2-(-2)

f(-1)= -2+2

f(-1)=0

to find 2f(-1) we have to multiply f(-1) value with 2

2f(-1)=2×0=0