Math, asked by shamim9, 1 year ago

f(x)=2x³ how to find f'(x)
given ans. is 6(2x)²=24x²

rajesh139: f(x)=2x^3 then d f(x)/dx=d(2x^3)/dx

rajesh139: f'(x)=2*3x^2/2

rajesh139: f'(x)=3x^2

shamim9: bro it doesn't match with the given ans. on the book

rajesh139: what are options given in text book

Answers

Answered by HappiestWriter012

f(x) = 2x³

If f(x) = x^n = nx^n-1 .

f'(x) = 2 * 3 ( x ^ 3 - 1 ) = 6x² .

Hope helped!

shamim9: but it didn't match the given answer on the book .... anyway thanks for the help

rajesh139: ok

rajesh139: 3x^2

shamim9: given answer is 6(2x)² = 24x²

siddhartharao77: I think its wrong answer @Shamim9.

rajesh139: the correct answer is f'(x)=3x^2

shamim9: probably......

Answered by siddhartharao77

Given f(x) = 2x^3

$f'(x) = \frac{d}{dx} x^3$

$= 2 * 3x^{3 - 1}$

6x^2.

Hope this helps!

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