f(x)=2x³ how to find f'(x)
given ans. is 6(2x)²=24x²
rajesh139:
f(x)=2x^3 then d f(x)/dx=d(2x^3)/dx
f'(x)=2*3x^2/2
f'(x)=3x^2
bro it doesn't match with the given ans. on the book
what are options given in text book
Answers
Answered by
7
f(x) = 2x³
If f(x) = x^n = nx^n-1 .
f'(x) = 2 * 3 ( x ^ 3 - 1 ) = 6x² .
Hope helped!
If f(x) = x^n = nx^n-1 .
f'(x) = 2 * 3 ( x ^ 3 - 1 ) = 6x² .
Hope helped!
but it didn't match the given answer on the book .... anyway thanks for the help
ok
3x^2
given answer is 6(2x)² = 24x²
I think its wrong answer @Shamim9.
the correct answer is f'(x)=3x^2
probably......
Answered by
1
Given f(x) = 2x^3
6x^2.
Hope this helps!
6x^2.
Hope this helps!
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