Question

f(x) = (3 − x)
2
x0 = 0
for (k = 0; k ≤ 10; k++)
{
d(xk) = f
0
(xk)
dd(xk) = d
0
(xk)
xk+1 = xk −
dd(xk)
} the value of x2 =​

Answer 1

Answer:

f(x) = (3 − x)

2

x0 = 0

for (k = 0; k ≤ 10; k++)

{

d(xk) = f

0

(xk)

dd(xk) = d

0

(xk)

xk+1 = xk −

dd(xk)

} the value of x2 =