f(x) = 3x – 1 g(x) = 5x + 2 and h(x) = x + 4 Find:- i) h(-7) = ii) f[g(2)] = iii) h[f(-1)] = iv) f[h(x)] = vi) h-1(3) =
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The answer is something which I don't know
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I) h(-7) = -7+4= 3
ii) f[g(2)] = f[5*2+2] = f[12]=3*12-1= 36-1=35
iii) h[f(-1)]=h[3*(-1)-1]= h[-4]= -4+4= 0
iv) f[h(x)]= f[x +4 ]= 3(x+4)-1= 3x+12-1= 3x+11
vi) unable to understand the question
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