Math, asked by jcpos1972, 2 months ago

f(x)=3x 2
+12x+5f, left parenthesis, x, right parenthesis, equals, 3, x, squared, plus, 12, x, plus, 5
What is the value of the discriminant of f?

Answers

Answered by shivani29052009
2

Answer:

Discriminant = 84

The polynomial has two real distinct roots

Step-by-step explanation:

Given: f(x)=3x^2+12x+5f(x)=3x

2

+12x+5

To find: discriminant of the given function and number of distinct real zeros

Solution:

For a polynomial f(x)=ax^2+bx+cf(x)=ax

2

+bx+c , discriminant is given by D=b^2-4acD=b

2

−4ac

If D > 0D>0 , then the polynomial has two real and distinct roots.

If D=0D=0 then the polynomial has two real and equal roots.

If D<0 then roots are not real.

Here, in f(x)=3x^2+12x+5f(x)=3x

2

+12x+5

a = 3, b = 12 and c = 5

D=(12)^2-4(3)(5)=144-60=84D=(12)

2

−4(3)(5)=144−60=84

As D > 0, the polynomial has two real distinct roots.

I hope it is useful for you

Answered by jeremymzhang
0

Answer:

84 is the discriminant, with 2 the possible answers.

Step-by-step explanation:

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