Question

f(x)=3x^2+24x+48 how many distinct real number zeros does f have

Answer 1

Answer:

3x^2+24x+48 = 0

given is a quadratic equation.

a = 3, b = 24, c = 48.

so let's find the value of discriminant,

D = b² - 4ac

= 24² - 4× 3 × 48

= 576 - 576

D = 0

so, D = 0, the roots are real and equal.

it has Only one distinct real zero.

Step-by-step explanation:

hope this helps u.

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