f(x)=3x-4 and (gof)(x)=x^2-6x+8 then find g(x)?
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we have given f(x) = 3x-4 and g(f(x))= x^2-6x+8
put x= (f(x)+4)/3 in x^2-6x+8
we get , let f(x) = y
then x=(y+4)/3
g(y)= (y+4)^2/9 -6((y+4)/3)+8
on solving we get
g(y) = (y^2-10y+16)/9
so g(x) = (x^2-10x+16)/9
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I don’t know if this is correct or not. Hope this helps you.
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