f ( x ) = 3x Square + 5 then find f ( y - 1 )
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Solution -
We have,
- f(x) = 3x² + 5
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We have to find f(y - 1).
- Put x = y - 1
➝ f(y - 1) = 3(y - 1)² + 5
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Using identity
- (a - b)² = a² + b² - 2ab
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➝ f(y - 1) = 3(y² + 1 - 2y) + 5
➝ f(y - 1) = 3y² + 3 - 6y + 5
➝ f(y - 1) = 3y² - 6y + 3 + 5
➝ f(y - 1) = 3y² - 6y + 8
⠀
Hence,
- f(y - 1) = 3y² - 6y + 8
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