Math, asked by harshavamsiannayafan, 21 hours ago

f(x)=3x square minus 1 x=minus 1/√3 and +2/√3​

Answers

Answered by motimarynazareth
0

Answer:

Sorry don't now the answer

Answered by adbhuvanvignesh
0

Answer:

+13

Step-by-step explanation:

 

(i) p(x)=3x+1,x=−1/3

 

On putting x=−1/3

 

p(x)=3x+1

p(−1/3)=3(−1/3)+1

=−1+1=0

∴−1/3 is a zero of p(x).

 

 

(ii) p(x)=5x–π, x=4/5

 

For, x=4/5

P(x)=5x-π

 

p(4/5)=5(4/5)–π

 

=4−π

 

4/5 is not a zero of p(x).

 

(iii) p(x)=x²−1,x=1,−1

On putting, x=1,−1

 

p(x)=x²−1

p(1)=(1)²−1

=1−1

=0

p(−1)=(-1)²−1

=1−1=0

1,−1 are zeros of p(x).

 

(iv) p(x)=(x+1)(x–2),x=−1,2

 

On putting, x=−1,2

 

p(x)=(x+1)(x–2)

p(−1)=(−1+1)(−1–2)

=((0)(−3))

=0

p(2)=(2+1)(2–2)

=(3)(0)

=0

−1,2 are zeros of p(x).

 

(v) p(x)=x²,x=0

On putting x=0

 

p(x)=0² =0

∴0 is a  zero of p(x).

 

(vi) p(x)=lx+m,x=−m/l

 

On putting ,x−m/l

p(x)=lx+m

∴p(−m/l)=l(−m/l)+m

=−m+m=0

∴−m/l is a zero of p(x).

 

(vii) p(x)=3x²−1,

x=−1/√3 ,2/√3

On putting x=−1/√3 ,2/√3

p(x)=3x²−1

 

p(−1/√3)=3(−1/√3)²−1

 

=3(1/3)−1

 

=1−1=0

 

p(2/√3)=3(2/√3)²−1

 

=3(4/3)−1

 

=4−1=3≠0

−1/√ 3 is a zero of p(x) but 2/√3 is not a zero of p(x).

 

(viii) p(x)=2x+1,x=1/2

On putting , x=1/2

 

p(x)=2x+1

p(1/2)=2(1/2)+1

=1+1=2≠0

1/2 is not a  zero of p(x).

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