Math, asked by keerthipinjala, 6 months ago

f(x),=3x3+x2-20x+12 . g(x) =3x-2

Answers

Answered by venkatesh3856
7
Hear is your answer hope it helps you
Attachments:
Answered by usha977113
5

Answer:

f(x)= 3x^3+x^2-20x+12

g(x)=3x-2=0

3x=0+2

3x=2

x= 2/3

now,

f(2/3) = 3(2/3)^3+(2/3)^2-20×2/3+12

= 8/9 +4/9-40/3+12

8+4-120+108+12/9

12_12/9

0/9.

= 0ans

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