Question

F(x)=4-x^2; f'(-3),f'(0),f'(1). find values of derivatives

Answer 1

f(x)=4-x^2
f'(x)=-2x
thus, f'(-3)=6
and f'(0)=0
f'(1)=-2

Answer 2

If f(x)= 4 - x^2
f'(x)= - 2x
Now put x= -3,0 ,1 to get ans