f(x)=(4-(x-7)^(3))^(1/5) then f^-1 (x)
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f(x)=4−(x−7) 3
Let y=f(x)
So, x=f −1 (y) ---- ( 1 )
y=f(x)
⇒ y=4−(x−7) 3
⇒ (x−7) 3 =4−y
⇒ x−7= 3 4−y
⇒ x=7+ 3 4−y
⇒ f −1 (y)=7+ 34−y .................. [ From ( 1)]
∴ f −1 (x)=7+ 34−x
I Hope Its Helpful to u dear
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