Math, asked by nayan3591, 16 days ago

F(x) = 4x2 – 17x + 3 What is the value of the discriminant of f? how many distinct real number zeros does f have?

Answers

Answered by vazimohd
109

Answer:

discriminant = b2-4ac

discriminant = (-17)^2-4(4)(3)

discriminant = 289-48

discriminant = 241

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Answered by abhi569
127

Answer:

241

2

Step-by-step explanation:

Discriminant of f(x) = ax^2 + bx + c is given by b^2 - 4ac.   Therefore,

On comparing this with ax^2 + bx + c,  we get

       a = 4   ;  b = -17      ;  c = 3

∴ Δ  = (-17)^2 - 4(4)(3)

       = 289 - 48

      = 241

Since it is quadratic(2-degree), it should have 2 solutions.  As discriminant is +ve, non-zero, not perfect square and real, roots are real, irrational and unequal.

 f(x) have 2 distinct real number zeroes.

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