f(x)=4x³+20x²+33x+18,g(x)=2x+3,Use the Factor Theorem to determine whether g(x) is factor of f(x) in each cases.
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Solution :
*******************************************
Factor Theorem :
Let p(x) be a polynomial of degree
one or more than 1 and a is a real
number. Then ,
i ) x - a , will be a factor of p(x) if
p(a) = 0 conversely
ii ) If ( x - a ) is a factor of p(x) , then
p(a) = 0.
*********************************************
Given
f(x) = 4x³ + 20x² + 33x + 18 ,
g(x) = 2x + 3 ,
g(x) = 0
=> 2x + 3 = 0
=> x = -3/2
Now , f( -3/2 )
= 4(-3/2)³ + 20(-3/2)² + 33(-3/2) + 18
= 4(-27/8) + 20(9/4) - 33(3/2 ) + 18
= -27/2 + 5 × 9 - 99/2 + 18
= ( -27 - 99 )/2 + 45 + 18
= - 126/2 + 63
= - 63 + 63
= 0
••••
*******************************************
Factor Theorem :
Let p(x) be a polynomial of degree
one or more than 1 and a is a real
number. Then ,
i ) x - a , will be a factor of p(x) if
p(a) = 0 conversely
ii ) If ( x - a ) is a factor of p(x) , then
p(a) = 0.
*********************************************
Given
f(x) = 4x³ + 20x² + 33x + 18 ,
g(x) = 2x + 3 ,
g(x) = 0
=> 2x + 3 = 0
=> x = -3/2
Now , f( -3/2 )
= 4(-3/2)³ + 20(-3/2)² + 33(-3/2) + 18
= 4(-27/8) + 20(9/4) - 33(3/2 ) + 18
= -27/2 + 5 × 9 - 99/2 + 18
= ( -27 - 99 )/2 + 45 + 18
= - 126/2 + 63
= - 63 + 63
= 0
••••
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