Question

f x-√5 is a factor of the cubic polynomial x3-3√5x2+13x-3√5 , then find all the zeroes of the polynomial

Answer 1

Answer:

Step-by-step explanation:

First, dividing the equation p(x)=x3 -3√5x2+13x-3√5 with f(x)= x-√5 we get q(x)= x2-2√5x+3 and r(x)=0

Now, solving for roots of q(x) using -b+-√b²-4ac /2a we get x= √5+√2 and √5-√2 and x= √5