f(x)=6x^2+10x−1
What is the value of the discriminant of f?
Answers
Answered by
3
hi there mate!!!
here,
6x^2+10x-1= 0
now,
comparing it with ax^2+bx+c= 0,
we get,
a= 6, b= 10,c= -1.
now,
discriminant= b^2-4ac
= (10) ^2-4×6×(-1)
= 100+ 24
= 124
here,
124> 0
hence,
the roots are real and unequal
hope this helps!! ♥❤
Answered by
1
b2-4ac= 10*10-4(6)(-1)
=100+24
124 (real and distinct)
Similar questions