f(x)= (6x)^⅓ find f'(x)
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f(x) = (6x)^⅓
Differentiating both sides w.r.t. x we get,
f'(x) = ⅓ × 6/(6x)^⅔
___= 2/(6x)^⅔
Hope this is ur required answer.
Differentiating both sides w.r.t. x we get,
f'(x) = ⅓ × 6/(6x)^⅔
___= 2/(6x)^⅔
Hope this is ur required answer.
shamim9:
hey bro can u explan me how 6/6x^⅔ came from...
yup why not...
I first took (6x)^⅓ as y⅓ and Differentiating we get 1/3 × y^-⅔
and dy/dx.
now dy/dx = d(6x)/dx = 6.
so I got ⅓×6 × (6x)^-⅔
thank you..
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