Question

f(x) = 6x²-5x-1 find the sum​

Answer 1

Answer:

sum of zeroes = 5/6

Step-by-step explanation:

f(x) = 6x²-5x-1

$=>6x^2-5x-1=0\\ 6x^2-6x+x-1=0 \\ 6x(x-1)+1(x-1)=0 \\ (x-1)(6x+1)=0 \\\\ =>x-1=0;x=+1 \\ =>6x+1=0;x=-1/6$

the zeroes of the polynomial are +1 and -1/6

$sum \ of \ zeroes=+1+(\frac{-1}{6} ) \\\\ sum \ of \ zeroes=1-\frac{1}{6} \\\\ sum \ of \ zeroes=\frac{6-1}{6} \\\\ sum \ of \ zeroes=\frac{5}{6}$

[OR]

f(x) = 6x²-5x-1

it is of the form ax²+bx+c

→ a = 6,b = -5,c = -1

⇒ sum of zeroes = -b/a

                            = -(-5)/6

                            = 5/6

Answer 2

Answer:

6X²-3x-2x-1

6X²-3x-2x-13x(2x-1)-1(2x-1)

6X²-3x-2x-13x(2x-1)-1(2x-1)(3x-1)(2x-1)

6X²-3x-2x-13x(2x-1)-1(2x-1)(3x-1)(2x-1)3x-1=0 or 2x-1=0

6X²-3x-2x-13x(2x-1)-1(2x-1)(3x-1)(2x-1)3x-1=0 or 2x-1=03x=1 or 2x=1

6X²-3x-2x-13x(2x-1)-1(2x-1)(3x-1)(2x-1)3x-1=0 or 2x-1=03x=1 or 2x=1X=1/3 or X=1/2