f (x) = ( a-be^-x)^e differentiation
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Answered by
0
Answer:
Let y=(ax−5)e
3x
On differentiating, we get
∴
dx
dy
=e
3x
(a)+(ax−5)3e
3x
(
dx
dy
)
x=0
=e
0
(a)+(a(0)−5)3e
0
=−13
−13=a−15⇒a=2
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