Math, asked by madhukeshri8277, 9 months ago

f(x)= abx² + ( b²-ac)x-bc

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Answered by MяƖиνιѕιвʟє
3

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= abx² + (- ac)x - bc

= abx²+x-acx-bc

= bx(ax+b)-c(ax+b)

= (ax+b)(bx-c)

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