Question

f(x)=anxn+an−1xn−1+...+a1x+a0f(x)=anxn+an−1xn−1+...+a1x+a0  and if  (a1−a0)+(a3−a2)+...=0(a1−a0)+(a3−a2)+...=0 ,  then one of the factors of f(x)f(x)  is​

Answer 1

Answer:

$a + b - c$

a+b+c==abc