Question

f(x) = ax -3x+14x-3 is divided by g(x) 3x-1 using remainder theoram​

Answer 1

$\huge\bold\red{Hey!}$

$3x - 1 = 0 \\ x = \frac{1}{3} \\ \\ g(x) = 3x - 1$

Now,

$f(x) = ax - 3x + 14x - 3 \\ \\ a \times \frac{1}{3} - 3 \times \frac{1}{3} + 14 \times \frac{1}{3} - 3 \\ \\ \frac{a}{3} - 1 + \frac{14}{3} - 3 \\ \\ \frac{a - 3 + 14 - 9}{3} \\ \\ \frac{a - 2}{3} = 0 \\ \\ a - 2 = 0 \\ \\ a = 2$