f(x) = ax+b and f(0) = 3, f(2) = 5,find the value of a and b
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Answered by
8
f(x) = ax + b
f(0) = a×0+ b
3= b+0
b = 3
f(2) = a×2+ b
5 = 2a + 3
2a = 5-3
a = 2/2 = 1
f(0) = a×0+ b
3= b+0
b = 3
f(2) = a×2+ b
5 = 2a + 3
2a = 5-3
a = 2/2 = 1
mah2:
No its wrong
Answered by
16
f(x) = ax+b
f(0)=a(0)+b
3 = 0+b
3=b
b = 3
f(x) = ax+b
f(2) = a(2)+b
5 = 2a + 3 [[[b=3]]]
5-3 =2a
2 = 2a
2/2 = a
1 = a
a=1
this is your answer.....
f(0)=a(0)+b
3 = 0+b
3=b
b = 3
f(x) = ax+b
f(2) = a(2)+b
5 = 2a + 3 [[[b=3]]]
5-3 =2a
2 = 2a
2/2 = a
1 = a
a=1
this is your answer.....
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