Question

F(x)= ax4 + bx2 + x + 5, F(-3)=2 what is the value of F(3)?

Answer 1

F(3)= a.3.4+b.3.2+3+5= 12a+ 6b +8

now acc. to question
F(-3)= 2
a.(-3).4+b.(-3).2 -3 + 5=2
-12a-6b+2=2
-12a-6b=0
2a+b=0
b=-2a


substitution in very first equation
12a+ 6.(-2a) +8
12a-12a+8
8 answer

Answer 2

Answer:

HEY MATE

YOUR ANSWER IS -5

but this one is not English this is math