Question

f (x) = axtb, f(3) =3, f (2) = 1, a=?, b= 2​

Answer 1

Answer:

Given that

f=(1,1),(2,3),(3,5),(4,7)

f(x)=ax+b....(1)

Now,

f=(1,1)

Then,

f(1)=ax+b

f(1)=a×1+b

1

a+b=1

−

2

a

−

+

b=

−

3

on subtracting

−a=−2

a=2 put in equation (2)

b+2=1

b=1−2=−1

b=−1

Hence this is the answer.