f(x)=cos⁴x,find f'(x) for it.
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Answer:
-4 cos³x sinx
Step-by-step explanation:
differentiating cos⁴x as differentiationg x^n
we will get nx^x-1 so..
4 cos³x ---eq I
but instead of 'x' we're having "cos x"
so we have to differentiate it and multiply it to the eq I
dy/dx of cos x is.. -sinx
so the result is..
-4 cos³x sinx
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