Question

f(x)= e^2x.cos3x find f'(x)​

Answer 1

Answer:

f'(x) = -6e^(2x)*sin3x

because differentiation of e^(2x) is 2e^(2x), for cos3x its -3sin3x so on multiplying we get -6e^(2x)*sin3x

Hope you may get it

Mark as brainliest

Thank You...