Question

f x is a digit such that the number 18 x71 is a multiple of 3, then the possible value (s) of x are ​

Answer 1

Solution:-

As we know that number are divisible by 3 if the sum of all the individual digits is evenly divisible by 3.

Given number = 18x71

The sum of all the digits of 18x71

= 1 + 8 + 7 + 1 

= 17

17 is not divisible by 3, so we need 18, that is divisible by 3.

17 + 1 = 18

So, the values of x are 1, 4 and 7.

And, the numbers are 18171, 18471 and 18771

Answer.