f(x) is polynomial of degree 'n' with rational coefficients and 1+2i, 2-root3
5 are the three zeroes of f(x). Then the least value of 'n' is
1)5 2)4 3)3 4)6
Answers
Answered by
0
Answer:
correct option 1 :-5
Step-by-step explanation:
The coefficients are rational, the roots should be either rational or if irrational or complex, must occur in pairs with their conjugates.
∵1+2i,2−
3
and 5 are the three roots given.
The irrational root 2−
3
will have its conjugate 2+
3
a root as well.
Similarly, 1−2i is also a root.
∴ there exist at least 5 roots of f(x)=0 and hence least value of n is 5.
Similar questions