F(x) = max (3-x, 3+x, 6) is differentiable at
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Answered by
5
Given:
F(x) = max (3-x, 3+x, 6)
To Find:
The points where F(x) = max (3-x, 3+x, 6) is differentiable.
Solution:
F(x) can be split based on the different value of x .
When x > 3 ,
- F(x) = 3 + x
When x < -3 ,
- F(x) = 3 - x
When -3 ≤ x ≤ 3 ,
- F(x) = 6
If we observe the graph of the function, it is a piece wise linear graph.
And since graph is continuous at x = -3 and x = 3 but , they are sharp points.
F(x) = max (3-x, 3+x, 6) is differentiable at all points except x =3 and x = -3.
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Answered by
0
Answer:
it is wrong because it is worng
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