Math, asked by Maniry1547, 10 months ago

F(x) = max (3-x, 3+x, 6) is differentiable at

Answers

Answered by RitaNarine
5

Given:

F(x) = max (3-x, 3+x, 6)

To Find:

The points where F(x) = max (3-x, 3+x, 6) is differentiable.

Solution:

F(x) can be split based on the different value of x .

When x > 3 ,

  • F(x) = 3 + x

When x < -3 ,

  • F(x) = 3 - x

When  -3 ≤ x ≤ 3 ,

  • F(x) = 6

If we observe the graph of the function, it is a piece wise linear graph.

And since graph is  continuous at x = -3 and x = 3 but , they are sharp points.

F(x) = max (3-x, 3+x, 6) is differentiable at all points except x =3 and x = -3.

Attachments:
Answered by vuppala123456sumanth
0

Answer:

it is wrong because it is worng

Similar questions